x+2x+3x+4x=x^2

Solution for x+2x+3x+4x=x^2 equation:

x+2x+3x+4x=x^2

We move all terms to the left:

x+2x+3x+4x-(x^2)=0

determiningTheFunctionDomain
-x^2+x+2x+3x+4x=0

We add all the numbers together, and all the variables

-1x^2+10x=0

a = -1; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·(-1)·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10}{2*-1}=\frac{-20}{-2}
=+10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10}{2*-1}=\frac{0}{-2}
=0
$